Bob Burrow Net Worth 2018: What is this basketball player worth?

Bob Burrow was a professional basketball player who played Power forward / Center as number 6, 50. Burrow’s weight is 228 pounds. Burrow’s height is 6 ft 7 in. Burrow was born on July 29, 1934, in Malvern, Arkansas. This article takes a deep dive into Bob Burrow’s net worth.

Bob Burrow Career and Earnings/Salary

In high school, Bob Burrow played basketball for Wells (Wells, Texas). Burrow played basketball in college with, Lon Morris College (1952-1954), and Kentucky Wildcats men’s basketball (1954-1956) and started playing professionally in 1956. In the 1956 draft, Burrow was chosen number 8 in round 2 by the Rochester Royals. Burrow left the game of basketball in 1958.

Burrow played for the Rochester Royals during 1956 as well as the Minneapolis Lakers in 1957. Some of the highlights of Bob Burrow’s career included: Consensus second-team NCAA Men’s Basketball All-Americans, and Third-team All-American – Associated Press.

Burrow set a career record of 459 (5.7 ppg) points, 357 (4.4 rpg) rebounds, and 47 (0.6 apg) assists.

Bob Burrow Net Worth 2018

Basketball yearly earnings can range between a few thousand dollars and tens of millions of dollars per year, depending on a number of considerations. Although most professional NBA players make a salary of approximately $2 million, some with D-league crossover deals are paid as little as $50,000. The salary cap for National Basketball Association players is around $100 million, although currently no player makes anywhere near that much money. The top players earn close to $35 million. Outside of the NBA, yearly earnings can go below $20,000 per year for minor league teams.