Bob Elliott Net Worth 2018: What is this basketball player worth?

Bob Elliott was a professional basketball player who played Center / Power forward as number 55. Elliott’s weight is 225 pounds. Elliott’s height is 6 ft 9 in. Elliott was born on August 18, 1955, in Ann Arbor, Michigan. This article takes a deep dive into Bob Elliott’s net worth.

Bob Elliott Career and Earnings/Salary

In high school, Bob Elliott played basketball for Pioneer High School (Ann Arbor, Michigan) (Ann Arbor, Michigan). Elliott played basketball in college with Arizona Wildcats men’s basketball (1973-1977) and started playing professionally in 1977. In the 1977 draft, Elliott was chosen number 42 in round 2 by the Philadelphia 76ers. Elliott left the game of basketball in 1983.

Elliott played for the Sporting Club Gira during 1977-1978 as well as the New Jersey Nets in 1978-1981. Later, Elliott played for the Detroit Spirits throughout 1982-1983. Some of the highlights of Bob Elliott’s career included: 3× First-team All-Western Athletic Conference.

Bob Elliott Net Worth 2018

Basketball annual payments vary between a few thousand dollars and millions of dollars annually, depending on a number of factors. Although typical NBA players earn a salary of nearly $2 million, a small contingent of players with D-league crossover deals earn as little as $50,000. The salary cap for NBA players is approximately $100 million, although currently nobody brings in anywhere near that much money. The top players in the NBA earn close to $35 million. Outside of the NBA, annual payments can dip below $20,000 annually for minor league teams.