Bob Seymour Net Worth 2018: What is this NFL football player worth?
Bob Seymour was a professional football player who played Halfback (American football); Fullback (American football) as number 20. Seymour died on May 28, 1977, in Golden, Colorado. Seymour was born on June 13, 1916, in Wyandotte, Oklahoma. This page looks closely at Bob Seymour’s net worth.
Bob Seymour Career and Earnings/Salary
In high school, Bob Seymour played football for Commerce, Oklahoma. Seymour played college football on the University of Oklahoma team. In the 1940 NFL draft, Seymour was chosen number 88 in round 10.
In the past, Seymour played for the Washington Redskins, and Los Angeles Dons. Some of the highlights of Bob Seymour’s career included: NFL champion, and Pro Bowl selection.
Some of Seymour’s most prominent statistics include 20 Touchdowns, 14 Interceptions, and 1,146 Rushing yards.
Bob Seymour Net Worth 2018
NFL player salaries range heavily. At the low end, NFL rookies earn $400,000-$600,000 annually. At the top level, stars can make $50 million or more. The National Football League salary cap is around $170 million.
Bob Seymour net worth: football salary distribution
So what was NFL football player Bob Seymour’s net worth at the time of death? Our estimate for Bob Seymour’s net worth at death is:
Looking for other NFL football players? Check out these net worth articles: Barry Wagner, Chad Simpson, Nick Mullens, Karl Hankton, Andrew Tiller, Rich Gunnell, Earl Audet, Mike Lansford, Sam Acho, Kurt Kafentzis, and Wesley Walls.
