Bob Skoronski Net Worth 2018: What is this NFL football player worth?
Bob Skoronski is a professional football player who plays Offensive tackle as number 76. Skoronski was born on March 5, 1934, in Ansonia, Connecticut. Skoronski’s height is 6 ft 3 in. This page looks closely at Bob Skoronski’s net worth.
Image Credit: Green Bay Packers
Bob Skoronski Career and Earnings/Salary
In high school, Bob Skoronski played football for Fairfield College Preparatory School. Skoronski played college football on the Indiana Hoosiers football team. In the 1956 NFL draft, Skoronski was chosen number 56 in round Round five.
In the past, Skoronski played for the Green Bay Packers. Some of the highlights of Bob Skoronski’s career include: 5× History of the National Football League championship, 2× Super Bowl champion, 1 Pro Bowl selection, and Green Bay Packers Hall of Fame.
Bob Skoronski Net Worth 2018
National Football League salaries range dramatically. At the lowest level, NFL players make $400,000-$600,000 per year. At the top end, players can make $50 million or more. The NFL salary cap is around $175 million.
Bob Skoronski net worth: football salary distribution
So what is NFL football player Bob Skoronski’s net worth in 2018? Our estimate for Bob Skoronski’s net worth as of 2018 is:
Looking for other NFL football players? Check out these net worth articles: David Pollack, Andy Studebaker, Obi Melifonwu, Kevin Eakin, Billy Yates, Doug Worthington, Mike Pitts, Bruce Jarvis, Kevin Rutland, Brian Xanders, and Scott Burley.
