Bud Black is a pro baseball player who plays Pitcher / Manager for the Colorado Rockies as # 10. Black was born on June 30, 1957, in San Mateo, California. This page will take a closer look at Bud Black’s net worth.
Black bats Left and throws Left. Black debuted in the MLB on September 5, 1981 for the Seattle Mariners. In all, Black played for the Seattle Mariners, Kansas City Royals, Cleveland Indians, Toronto Blue Jays, San Francisco Giants, Cleveland Indians, San Diego Padres, Colorado Rockies, and Los Angeles Angels of Anaheim. Black’s career ended with the Cleveland Indians in 1995.
Some of Black’s most prominent statistics in the MLB included a Win-loss record (pitching) stat of 121-116, a Earned run average stat of 3.84, and a Strikeouts stat of 1,039. Some of the highlights of Bud Black’s career include: 2× World Series champion, and NL Manager of the Year.
Bud Black was last under contract in 1995, according to USA Today, with a 1 (1995) year package worth $400,000. Over the years, Black earned $600,000 in 1988, $600,000 in 1989, $800,000 in 1990, $1.8 million in 1991, $3 million in 1992, $2 million in 1993, $3 million in 1994, and $400,000 in 1995.
Player salaries can range widely. In Major League Baseball, the average player earns approximately $3 million every year. Top MLB players can get $25 million or more annually, and lower rated players make $1 million or less.
In the minor leagues, most contracts are worth less than $10,000 a year.
So what is baseball player Bud Black’s net worth in 2018? Our estimate for Bud Black’s net worth as of 2018 is: $12 million
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