Clay Harbor Net Worth 2018: What is this NFL football player worth?
Clay Harbor is a professional football player who plays Tight end for the New Orleans Saints as number 80. Harbor’s height is 6 ft 3 in. Harbor was born on July 2, 1987, in Libertyville, Illinois. This page looks closely at Clay Harbor’s net worth.
Image Credit: Keith Allison
Clay Harbor Career and Earnings/Salary
In high school, Clay Harbor played football for Dwight High School. Harbor played college football on the Missouri State Bears football team. In the 2010 NFL draft, Harbor was chosen number 125 in round 4.
In the past, Harbor played for the Philadelphia Eagles, Jacksonville Jaguars, New England Patriots, Detroit Lions, and New Orleans Saints. Some of the highlights of Clay Harbor’s career include: Associated Press first-team All-America honors.
Some of Harbor’s most prominent statistics include 8 Receiving touchdowns, 1,170 Receiving yards, and 114 Receptions.
Clay Harbor Net Worth 2018
NFL salaries range dramatically. At the lowest level, NFL players make between $400,000 and $600,000 per year. At the highest level, NFL players can make $50 million plus. The NFL salary cap is nearly $175 million.
Clay Harbor net worth: football salary distribution
So what is NFL football player Clay Harbor’s net worth in 2018? Our estimate for Clay Harbor’s net worth as of 2018 is:
Looking for other NFL football players? Check out these net worth articles: Mike Renfro, Deiondre’ Hall, Dwight McLean, Zach Azzanni, Mike Hartline, Roger Chanoine, Cordell Taylor, Paul Duhart, Bill Lange, Karl Hankton, and Darryl Byrd.
