Da’Ron Payne Net Worth 2018: What is this NFL football player worth?
Da’Ron Payne is a professional football player who plays Defensive tackle as number –. Payne’s height is 6 ft 2 in. Payne was born on May 27, 1997, in Birmingham, Alabama. Payne’s weight is 308 pounds. This page looks closely at Da’Ron Payne’s net worth.
Da’Ron Payne Career and Earnings/Salary
In high school, Da’Ron Payne played football for Shades Valley High School. Payne played college football on the Alabama Crimson Tide football team.
In the past, Payne played for the, U.S. Army All-American Bowl selection, Freshman College Football All-America Team Team selection, First Team All Southeastern Conference Team, 2018 Sugar Bowl Co-MVP, and 2018 College Football Playoff National Championship Co-MVP.
Da’Ron Payne Net Worth 2018
National Football League salaries range dramatically. At the starting level, NFL rookies earn as much as $400,000 to $600,000 a year. At the highest, NFL players can bring in $50 million plus. The NFL salary cap is approximately $175 million.
Da’Ron Payne net worth: football salary distribution
So what is NFL football player Da’Ron Payne’s net worth in 2018? Our estimate for Da’Ron Payne’s net worth as of 2018 is:
Looking for other NFL football players? Check out these net worth articles: Therrian Fontenot, Willie Pile, Terry Randolph, Nick Sirianni, Chris T. Jones, Steven Black, Phillip Gaines, Cedric Figaro, Bruce Armstrong, Chris Boniol, and De’von Hall.
