Dave Szott Net Worth 2018: What is this NFL football player worth?
Dave Szott is a professional football player who plays Guard (American football) as number 79. Szott was born on December 12, 1967, in Passaic, New Jersey. Szott’s height is 6 ft 4 in. This page looks closely at Dave Szott’s net worth.
Dave Szott Career and Earnings/Salary
In high school, Dave Szott played football for Clifton High School (New Jersey). Szott played college football on the Penn State Nittany Lions football team. In the 1990 NFL draft, Szott was chosen number 180 in round 7.
In the past, Szott played for the Kansas City Chiefs, Washington Redskins, and New York Jets. Some of the highlights of Dave Szott’s career include: First-team All-Pro, and USA Today High School All-American.
Some of Szott’s most prominent statistics include 177 Games Played, and 171 Games Started.
Dave Szott Net Worth 2018
NFL salaries range significantly. At the low end, NFL rookies earn between $400,000 and $600,000 per year. At the highest, players can earn $50 million plus. The National Football League salary cap is approximately $175 million.
Dave Szott net worth: football salary distribution
So what is NFL football player Dave Szott’s net worth in 2018? Our estimate for Dave Szott’s net worth as of 2018 is:
Looking for other NFL football players? Check out these net worth articles: Mewelde Moore, Brad Edwards, Karl Rubke, Clarence Spiegel, Marcus Turner, Zane Gonzalez, Chip Kelly, Baron Batch, Bobby Thompson, Greg Johnson, and David Lofton.
