Ira Terrell Net Worth 2018: What is this basketball player worth?

Ira Terrell was a professional basketball player who played Power forward / Center as number 32, 34, 33. Terrell’s height is 6 ft 8 in. Terrell’s weight is 200 pounds. Terrell was born on June 19, 1954, in Dallas, Texas. This article takes a deep dive into Ira Terrell’s net worth.

Ira Terrell Career and Earnings/Salary

In high school, Ira Terrell played basketball for Franklin D. Roosevelt High School (Dallas, Texas)(Dallas, Texas). Terrell played basketball in college with SMU Mustangs men’s basketball (1972-1976) and started playing professionally in 1976. In the 1976 draft, Terrell was chosen number 45 in round 3 by the Phoenix Suns. Terrell left the game of basketball in 1979.

Terrell played for the Phoenix Suns during 1976 as well as the Utah Jazz in 1978. Later, Terrell played for the Portland Trail Blazers throughout 1979.

Ira Terrell Net Worth 2018

Basketball annual payments range between $20,000 and millions of dollars annually, depending on a number of factors. Although most professional NBA players make a salary of approximately $2 million, some with D-league crossover agreements are paid as little as $50,000. The salary cap for NBA players is approximately $100 million, although as of today nobody makes anywhere near that much money. The top players in the NBA earn nearly $35 million. Outside of the NBA, salaries can dip below $20,000 annually for minor league teams.