John Drew Net Worth 2018: What is this basketball player worth?

John Drew was a professional basketball player who played Small forward / Shooting guard as number 22, 20. Drew was born on September 30, 1954, in Vredenburgh, Alabama. Drew’s weight is 205 pounds. Drew’s height is 6 ft 6 in. This article takes a deep dive into John Drew’s net worth.

John Drew Career and Earnings/Salary

In high school, John Drew played basketball for J. F. Shields (Beatrice, Alabama). Drew played basketball in college with Gardner-Webb Runnin’ Bulldogs men’s basketball (1972-1974) and started playing professionally in 1974. In the 1974 draft, Drew was chosen number 25 in round 2 by the Atlanta Hawks. Drew left the game of basketball in 1986.

Drew played for the Atlanta Hawks during 1974-1981 as well as the Utah Jazz in 1982-1984-. Later, Drew played for the Wyoming Wildcatters throughout 1984-1986. Some of the highlights of John Drew’s career included: 2× NBA All-Star, and NBA All-Rookie First Team.

Drew set a career record of 15,291 (20.7 ppg) points, 5,088 (6.9 rpg) rebounds, and 1,004 (1.4 spg) steals.

John Drew Net Worth 2018

Player annual payments vary between $20,000 and millions of dollars annually, depending on a number of circumstances. Although on average, NBA players make a salary of approximately $2 million, a small contingent of players with D-league crossover deals receive as little as $50,000. The salary cap for National Basketball Association players is nearly $100 million, although as of today no player earns anywhere near that much money. The top players earn around $35 million. Outside of the National Basketball Association, yearly earnings can dip below $20,000 annually for minor league teams.