K. J. Hippensteel Net Worth 2018: What is this tennis player worth?
K. J. Hippensteel is a tennis player who was born on May 8, 1980, in Roanoke, Virginia. This article will take a look at K. J. Hippensteel’s net worth.
K. J. Hippensteel Career, Earnings
Hippensteel lives in Roanoke, Virginia; Virginia, plays Left-handed (two-handed backhand) and attended Stanford University. K. J. Hippensteel’s professional career began in 2002 and ended in retirement in the year 2008.
Over an accomplished career, Hippensteel won a total of 0 singles titles, won a total of 0 doubles titles and earned a total of $134,558 from competition. Hippensteel has won 0 singles titles, with a record of 1-3 and reached a rank of No. 150 (November 15, 2004). Hippensteel has won 0 doubles titles, with a record of 0-2 and reached a rank of No. 210 (October 25, 2004) in doubles play.
K. J. Hippensteel has an Australian Open record of Q3 (2008); a French Open junior record of Q1 (2008); a Wimbledon junior record of Q1 (2008); and a US Open junior record of achieving a number one ranking (2004).
K. J. Hippensteel competed in doubles events with good results, including a Wimbledon Doubles record of achieving a number one ranking (2008); and a US Open Doubles record that includes achieving a number one ranking (1998, 1999).
K. J. Hippensteel Net Worth 2018
So what is K. J. Hippensteel’s net worth in 2018? Hippensteel earned a total of $134,558 from competition according to Wikipedia, but that’s not all of Hippensteel’s earnings, which may include sponsorships, businesses, and promotions. Our estimate for K. J. Hippensteel’s net worth in 2018 is:
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