Lee Stevens Net Worth 2018: What is this baseball player worth?
Lee Stevens is a pro baseball player who plays First baseman. Stevens was born on July 10, 1967, in Kansas City, Missouri. This page will take a closer look at Lee Stevens’s net worth.
Lee Stevens Career, Earnings
Stevens bats Left and throws Left. Stevens debuted in the MLB on July 16, 1990 for the California Angels. In all, Stevens played for the California Angels, Kintetsu Buffaloes, Texas Rangers, Montreal Expos, and Cleveland Indians. Stevens’s career ended with the Cleveland Indians in 2002.
Some of Stevens’s most prominent statistics in the MLB included a Batting average stat of .254, a Home runs stat of 144, and a Run batted in stat of 531.
Lee Stevens Net Worth 2018
Lee Stevens was last under contract in 2002, according to USA Today, with a 1 (2002) year package worth $4 million. Over the years, Stevens earned $100,000 in 1990, $100,000 in 1992, $200,000 in 1997, $1.2 million in 1998, $2 million in 1999, $4 million in 2000, $4 million in 2001, and $4 million in 2002.
Baseball pay can range widely. In Major League Baseball, the median pay is near $3 million every year. Top players can get $25 million or more annually, and less successful players make $1 million or less.
Lee Stevens net worth: soccer/football salary distribution
In the minor leagues, most contracts pay less than $10,000 a year. Interesting data from Wikipedia about the contracts signed by Lee Stevens include:
- “He signed with the Kintetsu Buffaloes in Japan after the 1993 season; he would get $425,000 for 1994, with an option for a second year.”
So what is baseball player Lee Stevens’s net worth in 2018? Our estimate for Lee Stevens’s net worth as of 2018 is: $15 million
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