Sandy McDermott Net Worth 2018: What is this baseball player worth?
Sandy McDermott was a pro baseball player who played Second baseman. McDermott was born on March 15, 1856, in Zanesville, Ohio. McDermott died on November 23, 1922, in Mansfield, Ohio. This page will take a closer look at Sandy McDermott’s net worth.
Sandy McDermott Career, Earnings
McDermott batted Unknown and threw Unknown. McDermott debuted in the MLB on June 18, 1885 for the Baltimore Orioles (19th century). In all, McDermott played for the Baltimore Orioles. McDermott’s career ended with the Baltimore Orioles (19th century) in 1885.
Some of McDermott’s most prominent statistics in the MLB included a Games played stat of 1, and a At bats stat of 0.
Sandy McDermott Net Worth 2018
Player earnings can range widely. In professional baseball, the average player earns about $3 million every year. Top MLB players can get $25 million or more per annum, and lower rated players bring in $1 million or less. In the minor leagues, most contracts pay less than $10,000 a year.
Sandy McDermott net worth: baseball salary distribution
So what was baseball player Sandy McDermott’s net worth at the time of death? Our estimate for Sandy McDermott’s net worth at death is:
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