Sean Kilpatrick Net Worth 2018: What is this basketball player worth?

Sean Kilpatrick is a professional basketball player who plays Shooting guard for the Milwaukee Bucks as number 9. Kilpatrick’s height is 6 ft 4 in. Kilpatrick’s weight is 212 pounds. Kilpatrick was born on January 6, 1990, in Yonkers, New York. This article takes a deep dive into Sean Kilpatrick’s net worth.

Sean Kilpatrick Career and Earnings/Salary

In high school, Sean Kilpatrick played basketball for White Plains Senior High School (White Plains, New York)Notre Dame Preparatory School (Fitchburg, Massachusetts)(Fitchburg, Massachusetts). Kilpatrick played basketball in college with Cincinnati Bearcats men’s basketball (2010-2014) and started playing professionally in 2014. Kilpatrick was first drafted in 2014.

Kilpatrick played for the Santa Cruz Warriors during 2014-2015 as well as the Delaware 87ers in 2015. Later, Kilpatrick played for the Minnesota Timberwolves throughout 2014, the Delaware 87ers over 2015-2016, the Denver Nuggets during 2015, and the Brooklyn Nets during 2015 2017-. Some of the highlights of Sean Kilpatrick’s career include: All-NBA Development League Team, NBA Development League All-Star Game, Consensus second-team NCAA Men’s Basketball All-Americans, First-team All-American Athletic Conference, and 2× Second-team All-Big East Conference.

Sean Kilpatrick Net Worth 2018

Basketball player salaries can range between a few thousand dollars and millions of dollars per year, depending on a number of considerations. Although typical NBA players earn a salary of approximately $2 million, some with D-league crossover contracts are paid as little as $50,000. The salary cap for NBA players is around $100 million, although as of today no player makes anywhere near that much money. The top players earn approximately $35 million. Outside of the National Basketball Association, annual payments can dip below $20,000 per year for minor league teams.