Shaun Gayle Net Worth 2018: What is this NFL football player worth?
Shaun Gayle is a professional football player who plays Safety (American football position) as number 23. Gayle’s height is 5 ft 11 in. Gayle was born on March 8, 1962, in Newport News, Virginia. This page looks closely at Shaun Gayle’s net worth.
Shaun Gayle Career and Earnings/Salary
In high school, Shaun Gayle played football for Bethel High School (Hampton, Virginia). Gayle played college football on the Ohio State Buckeyes football team. In the 1984 NFL draft, Gayle was chosen number 271 in round 10.
In the past, Gayle played for the Chicago Bears, and San Diego Chargers. Some of the highlights of Shaun Gayle’s career include: Pro Bowl, and Super Bowl champion.
Some of Gayle’s most prominent statistics include 2 Touchdowns, 278 Interception yards, and 16 Interceptions.
Shaun Gayle Net Worth 2018
National Football League salaries range significantly. At the lowest level, NFL rookies earn as much as $400,000 to $600,000 annually. At the top end, stars can earn $50 million plus. The NFL salary cap is around $175 million.
Shaun Gayle net worth: football salary distribution
So what is NFL football player Shaun Gayle’s net worth in 2018? Our estimate for Shaun Gayle’s net worth as of 2018 is:
Looking for other NFL football players? Check out these net worth articles: Myrt Basing, Jim Arellanes, Caleb King, Matt McChesney, LaBrandon Toefield, Alex Barron, Ifeanyi Ohalete, Jeff Francis, Trevon Hartfield, Stan Kozlowski, and Dwayne Woodruff.
