Steve Brodie Net Worth 2018: What is this baseball player worth?
Steve Brodie was a pro baseball player who played Outfielder. Brodie was born on September 11, 1868, in Warrenton, Virginia. Brodie died on October 30, 1935, in Baltimore, Maryland. This page will take a closer look at Steve Brodie’s net worth.
Steve Brodie Career, Earnings
Brodie batted Left and threw Right. Brodie debuted in the MLB on April 21, 1890 for the Boston Beaneaters. In all, Brodie played for the Boston Beaneaters, St. Louis Browns, Baltimore Orioles, Pittsburgh Pirates, Baltimore Orioles, Baltimore Orioles, and New York Giants. Brodie’s career ended with the New York Giants in 1902.
Some of Brodie’s most prominent statistics in the MLB included a Batting average stat of .303, a Home runs stat of 25, and a Run batted in stat of 900. Some of the highlights of Steve Brodie’s career included: National League pennant: 1891, 1894, 1895, 1896.
Steve Brodie Net Worth 2018
Baseball pay can range widely. In Major League Baseball, the median pay is around $3 million every year. Top players can get $25 million or more per annum, and lower paid players earn $1 million or less. Outside the MLB, most contracts pay less than $10,000 a year.
Steve Brodie net worth: baseball salary distribution
So what was baseball player Steve Brodie’s net worth at the time of death? Our estimate for Steve Brodie’s net worth at death is:
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