Tony Snell Net Worth 2018: What is this basketball player worth?

Tony Snell is a professional basketball player who plays Shooting guard for the Milwaukee Bucks as number 21. Snell’s weight is 221 pounds. Snell’s height is 6 ft 7 in. Snell was born on November 10, 1991, in Watts, Los Angeles. This article takes a deep dive into Tony Snell’s net worth.

Tony Snell Career and Earnings/Salary

In high school, Tony Snell played basketball for Martin Luther King High School (Riverside, California); (Riverside, California); Westwind Preparatory Academy; (Phoenix, Arizona). Snell played basketball in college with New Mexico Lobos men’s basketball (2010-2013) and started playing professionally in 2013. In the 2013 National Basketball Association draft, Snell was chosen number 20 in round 1 by the Chicago Bulls.

Snell played for the Chicago Bulls during 2013-2015 as well as the Milwaukee Bucks in 2016-present. Some of the highlights of Tony Snell’s career include: Third-team All-Mountain West Conference, and MWC Men’s Basketball Tournament MVP.

Tony Snell Net Worth 2018

Basketball salaries vary between a few thousand dollars and tens of millions of dollars annually, depending on a number of considerations. Although typical NBA players earn a salary of nearly $2 million, a small contingent of players with D-league crossover contracts are paid as little as $50,000. The salary cap for NBA players is around $100 million, although currently nobody brings in anywhere near that much money. The top players earn around $35 million. Outside of the National Basketball Association, salaries can be under $20,000 annually for minor league teams.